PHP数组对比函数,存在交集则返回真,否则返回假
author:一佰互联 2019-04-30   click:169
复制代码 代码如下:
<?php
$array1 = array("a", "b", "c", "d");
$array2 = array("a", "c");
$array3 = array_intersect($array1, $array2);
if($array3) {
echo "有交集";
}
?>